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5 votes
If tolower's argument is already lowercase, it will be inadvertently converted to uppercase.

A. True
B. False

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User K Hein
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1 Answer

3 votes

Final answer:

If the argument passed to tolower() is already lowercase, it will inadvertently be converted to uppercase.

Step-by-step explanation:

If tolower's argument is already lowercase, it will be inadvertently converted to uppercase. The correct answer is True. In programming languages like C++, the tolower() function is used to convert uppercase characters to lowercase. So, if the argument passed to tolower() is already lowercase, it will inadvertently be converted to uppercase. For example, if you call tolower('a'), it will return 'A'.

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User Severin
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