Question

Jar jar has an acceleration of 0.15 m/s². Jar jar reaches 0.85 m/s before the 3.4 second celebration is over. How far does Jar jar crawl?

A) 2.64 meters
B) 3.36 meters
C) 4.25 meters
D) 5.44 meters

Answer 1

To find the distance Jar jar crawls, use the kinematic equation s = ut + ½at². Upon substituting the given values, s is found to be approximately 3.757 meters, which is not one of the provided answer choices, suggesting there may be an error in the question.

Step-by-step explanation:

You want to calculate how far Jar jar crawls given an acceleration of 0.15 m/s² and a final velocity of 0.85 m/s before 3.4 seconds have passed. The distance covered under constant acceleration can be calculated using the kinematic equation:

s = ut + ½at²

Where:
s = distance traveled
u = initial velocity (which we'll assume is 0 since Jar jar is starting from rest)
a = acceleration
t = time

Substituting the given values into the equation:

s = 0 * 3.4 + ½ * 0.15 m/s² * (3.4 s)²

This simplifies to:

s = 0.5 * 0.15 * 11.56

s = 0.075 * 11.56

s = 0.867 m

However, we must correct this calculation because the initial velocity is actually not zero since we know Jar jar is already moving at 0.85 m/s at the end of the celebration. Therefore, we need to use the full kinematic equation:

s = ut + ½at²

s = 0.85 m/s * 3.4 s + ½ * 0.15 m/s² * (3.4 s)²

s = 2.89 m + 0.867 m

s = 3.757 m

So, Jar jar crawls approximately 3.757 meters, which is not exactly one of the provided options. There might be a mistake in the question or in the provided options. Please recheck the original question for any discrepancies.