Question

HEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEELP PEASE! Have steps in your answer so I get what to do, thanks a mil in advance!

Answer 1

1y^2- 7y +3

Explanation:

Answer 2

Answer:
`2y^4+4y^3-5y^2-7y+3`

Work Shown

`(y^2+y-3)(2y^2+2y-1)\\\\w(2y^2+2y-1) \ \ \text{.... see note1 }\\\\2y^2w+2yw-1w\\\\2y^2( w )+2y( w )-1( w )\\\\2y^2( y^2+y-3 )+2y( y^2+y-3 )-1( y^2+y-3 ) \ \text{ ... see note2 }\\\\( 2y^4+2y^3-6y^2 )+( 2y^3+2y^2-6y )+( -y^2-y+3 )\\\\2y^4+2y^3-6y^2 + 2y^3+2y^2-6y-y^2-y+3 \\\\2y^4+(2y^3 + 2y^3)+(-6y^2+2y^2-y^2)+(-6y-y)+3 \\\\2y^4+4y^3-5y^2-7y+3 \\\\`

• Note1: Let
  `w = y^2+y-3`
• Note2: Plug in
  `w = y^2+y-3`

I used GeoGebra to confirm the answer.