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Don has 5 pennies, 3 nickels, and 4 dimes. All coins of each denomination are indistinguishable. How many ways can he rearrange the coins in a row?

Don has 5 pennies, 3 nickels, and 4 dimes. All coins of each denomination are indistinguishable. How many ways can he rearrange the coins in a row?
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Don has 5 pennies, 3 nickels, and 4 dimes. All coins of each denomination are indistinguishable. How many ways can he rearrange the coins in a row?

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User David Nilosek
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8.6k points

1 Answer

2 votes

Answer:

12!/(5!3!4!) = 27,720

Don can arrange these coins in 27,720 ways.

answered
User Ken Yao
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8.7k points
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