Question

Three lettered balls are drawn at random from a jar containing six balls bearing the letters A -F. What is the probability that one of three balls drawn will be the one with A on it?

Answer 1

The probability that one of the three balls drawn will be the one with letter A on it is 0.05 or 5%.

Step-by-step explanation:

To calculate the probability that one of the three balls drawn will be the one with letter A on it, we need to find the total number of possible outcomes and the number of favorable outcomes.

There are 6 balls in total and 3 balls are drawn, so the number of possible outcomes is given by the combination formula : C(6,3)

= 6!/3!(6-3)!

= 20.

The number of favorable outcomes is 1, as there is only 1 ball with letter A on it.

Therefore, the probability is:

P(A) = favorable outcomes / total outcomes = 1/20

= 0.05 or 5%.