Question

a man holds a block from falling by pushing it horizontally against a vertical wall. if the block weighs 3.0 newtons and the coefficient of static friction between block and wall is 0.40, what force must he exert?

Answer 1

The man must exert a force of 1.2 Newtons.

Step-by-step explanation:

The force the man must exert to prevent the block from falling can be calculated using the equation:

Ffriction = μs * N

where Ffriction is the force of friction, μs is the coefficient of static friction, and N is the normal force.

In this case, the normal force is equal to the weight of the block, which is 3.0 N.

Substituting the given values, we have:

Ffriction = 0.40 * 3.0 N

Ffriction = 1.2 N

Therefore, the man must exert a force of 1.2 Newtons to prevent the block from falling.