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1 vote
A large balloon fashioned to look like a mole is designed for the Macy’s Thanksgiving Day Parade. If the volume of the balloon is 835 L after the addition of 588 moles of helium, how many more moles of helium must be added to fill the balloon to its final volume of 2953 L?

asked
User Mnk
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1 Answer

7 votes

Final answer:

To fill the balloon to its final volume of 2953 L from 835 L, an additional 1494 moles of helium are required.

Step-by-step explanation:

The question asks about how many more moles of helium need to be added to a balloon to increase its volume from 835 liters to 2953 liters.

We can use Avogadro's law which states that the volume of a gas is directly proportional to the number of moles of the gas when the pressure and temperature are held constant.

Initial volume (V1): 835 L
Initial moles (n1): 588 moles
Final volume (V2): 2953 L
The question asks for the final moles (n2).

According to Avogadro's Law, V1/n1 = V2/n2.
Let's rearrange the formula to solve for n2: n2 = V2 x (n1/V1)
So, n2 = 2953 L x (588 moles / 835 L)

= 2082 moles

The mole that was originally in the balloon is still there, so we subtract the original amount of moles to find the additional moles needed:
Additional moles needed = n2 - n1
Additional moles needed = 2082 moles - 588 moles

= 1494 moles

answered
User Yazan Rawashdeh
by
8.2k points
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