Final answer:
Using stoichiometry, 80g of calcium can react with sulfuric acid to produce 271.65 grams of calcium sulphate, assuming that sulfuric acid is in excess.
Step-by-step explanation:
To calculate the mass of calcium sulphate (CaSO4) that could be produced from 80g of calcium (Ca), we use stoichiometry. The reaction of calcium with sulfuric acid (H2SO4) is given by:
Ca + H2SO4 -> CaSO4 + H2
Firstly, we determine the molar mass of calcium, which is 40.08 g/mol. Since we have 80g of Ca, we can find out how many moles of calcium we have:
80 g Ca x (1 mol Ca / 40.08 g Ca) = 1.996 moles of Ca
From the balanced chemical equation, we see that 1 mole of Ca reacts with 1 mole of H2SO4 to produce 1 mole of CaSO4. Therefore, 1.996 moles of Ca would produce 1.996 moles of CaSO4.
The molar mass of CaSO4 is:
40.08 g/mol (Ca) + 32.07 g/mol (S) + (4 x 16.00 g/mol (O)) = 136.14 g/mol (CaSO4)
To find the mass of CaSO4 produced:
1.996 moles of CaSO4 x 136.14 g/mol (CaSO4) = 271.65 g of CaSO4
Therefore, the mass of calcium sulphate that could be produced from 80g of calcium, assuming unlimited sulfuric acid, is 271.65 grams.