How many grams of glucose (C₆H₁₂O₆) are there in 911.47 mL of a 15.63 %(m/v) glucose-water solution?

Question

asked Nov 26, 2024 58.7k views

1 Answer

Olaf Heinemann · Answer 1 · 2024-11-30T03:36:23+0000

There are 142.49 grams of glucose in 911.47 mL of the 15.63 %(m/v) glucose-water solution.

To find the number of grams of glucose in the solution, we can use the formula:

grams of solute = volume of solution (mL) * percent (m/v)

Plugging in the values from the question, we have:

grams of glucose = 911.47 mL * 15.63% = 142.49 g

Therefore, there are 142.49 grams of glucose in 911.47 mL of the solution.