asked 6.3k views
3 votes
Factor of (a² bc + ab² c+ abc²).

a. (a²b²c²(a + b + c))
b. (a²bc(a+b+c))
c. (abc(a + b + c))
d. (a²b²c²(a + b + c))

asked
User Anhoppe
by
8.4k points

1 Answer

2 votes

Final answer:

The expression (a²bc + ab²c + abc²) can be factored by taking out the common abc, resulting in (abc(a + b + c)).

Step-by-step explanation:

The question asks us to factor the expression (a²bc + ab²c + abc²). Upon inspecting the terms in the expression, we can see that they all share a common factor of abc. Factoring out the common abc from each term, we get:

abc(a + b + c)

This means that each of the original terms is made up of abc multiplied by one additional term, which represents the sum of a, b, and c. So, the correct answer is (c) (abc(a + b + c)).

answered
User Kun Li
by
8.9k points
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