Question

A die is thrown once. What is the probability of getting a number other than 4?

a) 1/6

b) 1/3

c) 1/2

d) 2/3

Answer 1

The probability of getting a number other than 4 when a die is thrown once is 5 out of 6 possible outcomes, which simplifies to 2/3.

Step-by-step explanation:

The question asks for the probability of getting a number other than 4 when a die is thrown once. A standard six-sided die has six possible outcomes: 1, 2, 3, 4, 5, and 6. Only one of these outcomes is a 4. Therefore, the number of favorable outcomes for getting a number other than 4 is 5 (since we have 1, 2, 3, 5, and 6 as possible outcomes). The total number of possible outcomes is 6. To find the probability, we divide the number of favorable outcomes (5) by the total number of outcomes (6).

P(not 4) = Number of favorable outcomes / Total number of outcomes = 5 / 6.

Therefore, the correct answer is d) 5/6 or 2/3 after simplification.