Question

What is the equation of the quadratic graph with a focus of (5, −1) and a directrix of y=1?

A.f(x)=−1/4(x−5)²+1
B.f(x)=1/4(x−5)²+1
C.f(x)=−1/4(x−5)²
D.f(x)=1/4(x−5)²

Answer 1

The equation of the quadratic graph with a focus of (5, -1) and a directrix of y = 1 is (B) f(x) = 1/4(x-5)² + 1.

Step-by-step explanation:

Directrix and Focus: A parabola is defined as the set of all points equidistant to the focus and the directrix. Since the directrix is horizontal (y = 1), the parabola opens upwards and the axis of symmetry is vertical (x = 5).