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What is the equivalent resistance of the circuit?

[ 10.0 Omega parallel (120.0 Omega + 20.0 Omega + 30.0 Omega) ]

a) (2.00 Omega)
b) (60.0 Omega)
c) (0.500 Omega)
d) (120.0 Omega)

asked
User Aliah
by
9.1k points

1 Answer

0 votes

Final answer:

The equivalent resistance of the circuit is 17.5 Ω

Step-by-step explanation:

To find the equivalent resistance of the circuit, we need to calculate the total resistance of the parallel combination and then add it to the resistance in series. The parallel combination is made up of three resistors: 120.0 Ω, 20.0 Ω, and 30.0 Ω. To calculate their total resistance, we use the formula:

1/Rp = 1/R1 + 1/R2 + 1/R3

Plugging in the values, we get:

1/Rp = 1/120 + 1/20 + 1/30

Simplifying, we find Rp = 7.5 Ω.

Now we add the resistance in series, which is 10.0 Ω. The equivalent resistance of the circuit is then:

Requivalent = Rp + Rseries = 7.5 + 10.0 = 17.5 Ω

answered
User DappWind
by
8.2k points

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