asked 123k views
3 votes
Use the Squeeze Theorem to evaluate the limit. (Give your answer as a whole number.) lim_{(x, y)->(9,4)}(x^2-81)cos(1/(x-9)^2+(y-4)^2)="

asked
User Mdlars
by
8.6k points

1 Answer

4 votes

Final answer:

Using the Squeeze Theorem, we find the limit of the provided function as (x, y) approaches (9, 4) to be 0, since the term (x^2-81) approaches 0 and the cosine function is bounded between -1 and 1.

Step-by-step explanation:

To evaluate the limit using the Squeeze Theorem, we must find two functions that squeeze our given function. Since the cosine function oscillates between -1 and 1, we can say that:

-|x^2-81| ≤ (x^2-81)·cos(1/(x-9)^2 + (y-4)^2) ≤ |x^2-81|

As (x, y) approaches (9, 4), the term (x^2-81) approaches 0. So both the lower and upper bounding functions approach 0. Therefore, according to the Squeeze Theorem, the limit of the original function as (x, y) approaches (9, 4) is also 0.

It is not necessary to integrate or extensively use trigonometric identities here; we are simply using the properties of cosine and the bounds provided by its range to determine the limit of the entire function.

answered
User Flea
by
7.0k points
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.