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Second Order Equations-Variation of Parameters: Problem 1 (1 point) In this problem you will solve the rqn-homogeneous differential equation y ′′+16y=sec² (4x) on the interval −π/8 (1) Let C₁ and C₂ be arbitrary constants. The general solution of the related homogeneous differential equation y

′′+16y=0 is the function yh(x) = C₁ y₁ (x) + C₂ y₂ (x) = C₁ ____ + _____ C₂ .

1 Answer

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Final answer:

The general solution of the related homogeneous differential equation is yh(x) = C₁ y₁ + C₂ y₂.

Step-by-step explanation:

The general solution of the related homogeneous differential equation y ′′+16y=0 is the function yh(x) = C₁ y₁ (x) + C₂ y₂ (x) = C₁ y₁ + C₂ y₂.

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User Tugay
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