Question

For what value does the function fail to exist?
f(x)= 9/x³+27

Answer 1

The function fails to exist when the denominator, x³ + 27, equals zero. Therefore, the function f(x) fails to exist at x = -3.

Step-by-step explanation:

The function fails to exist when the denominator, x³ + 27, equals zero. To find the value of x for which this occurs, we set the denominator equal to zero and solve for x.

x³ + 27 = 0

Subtracting 27 from both sides, we get:

x³ = -27

Taking the cube root of both sides, we find:

x = -3

Therefore, the function f(x) fails to exist at x = -3.