Question

What are the Kpa of the following
+ Ka = 1.3 × 10⁻⁵, Ka = 5.6 × 10⁻¹⁰?

Answer 1

For the given acid dissociation constants (Ka) of + Ka = 1.3 × 10⁻⁵ and Ka = 5.6 × 10⁻¹⁰:

1. Ka = 1.3 × 10⁻⁵:

The acid dissociation constant (Ka) is 1.3 × 10⁻⁵.

2. Ka = 5.6 × 10⁻¹⁰:

The acid dissociation constant (Ka) is 5.6 × 10⁻¹⁰.

Step-by-step explanation:

The acid dissociation constant (Ka) is a measure of the extent to which an acid ionizes in a solution. It is an equilibrium constant that describes the ratio of the concentrations of the dissociated ions to the undissociated molecules in the dissociation of an acid.

In the provided information, two values of Ka are given:

1. For the acid with Ka = 1.3 × 10⁻⁵, it indicates a relatively stronger acid compared to the one with Ka = 5.6 × 10⁻¹⁰. A higher Ka value suggests greater ionization of the acid in solution.

2. For the acid with Ka = 5.6 × 10⁻¹⁰, it indicates a weaker acid, as its ionization is less extensive compared to the acid with Ka = 1.3 × 10⁻⁵.

These values are crucial in understanding the strength of acids and their behavior in solution.