Question

In a dihybrid cross for round and yellow seeds (RrYy x RrYy), what is the probability of having green and wrinkled seeds?

A) 1:16
B) 3:16
C) 8:16
D) 9:16

Answer 1

The probability of having green and wrinkled seeds in a dihybrid cross for round and yellow seeds is 1:16

Step-by-step explanation:

When performing a dihybrid cross for round and yellow seeds (RrYy x RrYy), the probability of having green and wrinkled seeds can be calculated using the product rule. We can assume that three quarters of the F2 generation offspring would be round (RR or Rr), and one quarter would be wrinkled (rr). Similarly, for seed color, we would expect three quarters of the F2 offspring to be yellow (YY or Yy) and one quarter to be green (yy). The probability of having green and wrinkled seeds is the product of the probabilities for each trait: (1/4) x (1/4) = 1/16. Therefore, the correct answer is A) 1:16.