Question

Assuming steady-state approximation for [Cl] and [COCl], what is the rate law for the formation of COCl2?

a) Rate = A3*[Cl][CO]
b) Rate = A5[Cl2][COCl]
c) Rate = A5[COCl2][Cl]
d) Rate = A3[COCl]*[Cl]

Answer 1

The rate law for the formation of COCl2, assuming steady-state approximation for [Cl] and [COCl], is c) Rate = A5[COCl2][Cl].

Step-by-step explanation:

The rate law for the formation of COCl2, assuming steady-state approximation for [Cl] and [COCl], is option

c) Rate = A5[COCl2][Cl].

In the steady-state approximation, the rate of formation of COCl2 is proportional to the concentration of COCl2 itself and the concentration of Cl. The rate constant A5 represents the proportionality constant in the rate law.