Question

The length of this rectangle is 2sqrt19, the width of the rectangle is sqrt19. The value of its perimeter is?

Answer 1

P = 6
`√(19)` units

A = 38 sq units

Explanation:

P = 2
`√(19)` + 2
`√(19)` + 1
`√(19)` + 1
`√(19)`

P = 6
`√(19)`

A = 2
`√(19)` ·
`√(19)`

A = 2 (19)

A = 38 sq units