Question

Write cell schematics for the following cell reactions, using platinum as an inert electrode as needed.

(a) Mg(s) + Ni²⁺(aq) → Mg²⁺(aq) + Ni(s)
(b) 2Ag⁺ (aq) + Cu(s) → Cu²+(aq) + 2Ag(8)
(c) Mn(s) + Sn(NO₃)₂ (aq) → Mn(NO₃)₂ (0)
(d) 3CuNO₃(aq) + Au(NO₃)₃(aq) → 3Cu(N)

Answer 1

To write the cell schematics, the oxidation and reduction processes are combined, and platinum is used as the inert electrode in the reaction involving gold (d). The schematics represent the electron flow from anode to cathode in each galvanic cell.

Step-by-step explanation:

To write the cell schematics for the given reactions, we need to identify the anode and cathode processes, which involve oxidation and reduction, respectively. The inert electrode, platinum, is used when a substance does not make a good electrode itself.

Mg(s) | Mg²⁺(aq) || Ni²⁺(aq) | Ni(s)

Ag⁺(aq) | Ag(s) || Cu(s) | Cu²⁺(aq)

Mn(s) | Mn(NO₃)₂(aq) || Sn(NO₃)₂(aq) | Sn(s)

Cu(NO₃)₂(aq) | Cu(s) || Au(NO₃)₃(aq) | Au(s), Pt (Pt as inert electrode)