Question

Within a motor, 30.0 A passes through a 250-turn circular loop with a radius of 10.0 cm. Determine the magnetic field strength created at its center.

a) 1.20 × 10-1T
b) 2.40 × 10-1T
c) 3.60 × 10-1T
d) 4.80 × 10-1 T

Answer 1

The magnetic field strength at the center of the circular loop is 3.60 × 10-1 T.

Step-by-step explanation:

The magnetic field strength at the center of a circular loop can be calculated using the formula:

B = (μ₀ * I * N) / (2 * R)

Where:

• B is the magnetic field strength
• μ₀ is the permeability of free space (4π × 10-7 T·m/A)
• I is the current passing through the loop (in amperes)
• N is the number of turns in the loop
• R is the radius of the loop (in meters)

By substituting the given values into the formula, we can calculate the magnetic field strength:

B = (4π × 10-7 T·m/A * 30.0 A * 250) / (2 * 0.1 m)

B = 3.60 × 10-1 T