Question

Find the area and perimeter of a TV set with dimensions 88 cm x 49 cm (to nearest cm). (Hint: find the upper and lower bounds to find the area and perimeter)​

Answer 1

Here

• Length=L=88cm
• Breadth=49cm=B

Note the formulas

`\boxed{\bf Perimeter=2(L+B)}`

`\boxed{\bf Area=LB}`

Now

`\\ \tt\hookrightarrow Perimeter=2(88+49)=2(137)=274cm`

`\\ \tt\hookrightarrow Area=88(49)=4312cm^2`

Answer 2

Given below.

Explanation:

For upper bound, the length is 88.5 cm and width is 49.5 cm

So, area of rectangle, TV = length * width

= 88.5 * 49.5

= 4380.75 cm²

So, perimeter = 2( length + width )

= 2( 88.5 + 49.5 )

= 276 cm

For lower bound, the length is 87.5 cm and width is 48.5 cm

So, area of rectangle, TV = length * width

= 87.5 * 48.5

= 4243.75 cm²

So, perimeter = 2( length + width )

= 2( 87.5 + 48.5 )

= 272 cm