asked 151k views
4 votes
Find the frequency of a tuning fork that takes (2.50 times 10⁻3 s) to complete one oscillation.

a) (200 Hz)
b) (300 Hz)
c) (400 Hz)
d) (500 Hz)

1 Answer

5 votes

Final answer:

The frequency of the tuning fork that takes 2.50 x 10⁻³ s to complete one oscillation is 400 Hz.

Step-by-step explanation:

The frequency of a tuning fork is the number of oscillations it completes in one second. To find the frequency of a tuning fork that takes 2.50 x 10-3 s to complete one oscillation, we take the reciprocal of the time taken:

Frequency = 1 / Time Period

Frequency = 1 / (2.50 x 10-3 s) = 400 Hz.

Therefore, the correct answer is c) (400 Hz).

answered
User Sandah Aung
by
7.5k points
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