Question

An experiment in a general chemistry laboratory calls for a 2.00-M solution of HCl. How many mL of 11.9 M HCl would be required to make 250 mL of 2.00 M HCl?

a) 42.02 mL
b) 84.04 mL
c) 168.08 mL
d) 336.16 mL

Answer 1

Using the dilution formula C1V1 = C2V2 and substituting the given values, we find the required volume of 11.9 M HCl to make a 250 mL solution of 2.00 M HCl.

The correct answer is none of these.

Step-by-step explanation:

To figure out how many mL of 11.9 M HCl is required to make 250 mL of 2.00 M HCl, we use the dilution formula C1V1 = C2V2, where C1 is the concentration of the starting solution, V1 is the volume we are solving for, C2 is the desired concentration, and V2 is the final volume of the diluted solution. We are given that C1 is 11.9 M, C2 is 2.00 M, and V2 is 250 mL.

By rearranging the equation, we get V1 = (C2 x V2) / C1. Substituting the known values, we have: V1 = (2.00 M x 250 mL) / 11.9 M, which yields V1 = 500mL / 11.9. Calculating this gives us the volume V1, which is the amount of 11.9 M HCl needed to prepare the solution.