Question

Which of the following atoms would be expected to form negative ions in binary ionic compounds and which would be expected to form positive ions: P, I, Mg, Cl, In, Cs, O, Pb, Co?

a) Negative: P, I, O; Positive: Mg, Cl, In, Cs, Pb, Co
b) Negative: I, O; Positive: P, Mg, Cl, In, Cs, Pb, Co
c) Negative: P, I, O, Cl; Positive: Mg, In, Cs, Pb, Co
d) Negative: I, O, Cl; Positive: P, Mg, In, Cs, Pb, Co

Answer 1

In a binary ionic compound, the nonmetals P, I, Cl, and O would form negative ions, whereas Mg, In, Cs, Pb, and Co being metals would form positive ions. The correct distribution is negative ions: P, I, O, Cl; positive ions: Mg, In, Cs, Pb, Co.

Step-by-step explanation:

Atoms are expected to form ions based on their position on the periodic table. Nonmetals typically form negative ions (anions), while metals typically form positive ions (cations).

Considering the atoms given (P, I, Mg, Cl, In, Cs, O, Pb, Co), phosphorus (P), iodine (I), chlorine (Cl), and oxygen (O) are nonmetals and would be expected to form negative ions.

On the other hand, magnesium (Mg), indium (In), cesium (Cs), lead (Pb), and cobalt (Co) are metals and would be expected to form positive ions. Therefore, the correct distribution of these atoms into ions that would form in binary ionic compounds would be:

• Negative ions: P, I, O, Cl
• Positive ions: Mg, In, Cs, Pb, Co

Based on this, the correct answer is option (c).