asked 106k views
5 votes
To sterilize a 50.0-g glass baby bottle, we must raise its temperature from 22.0°C to 95.0°C. How much heat transfer is required?

(a) 2.3 x 10⁴ J
(b) 3.1 x 10⁴ J
(c) 3.9 x 10⁴ J
(d) 4.7 x 10⁴ J

asked
User Randakar
by
7.7k points

1 Answer

1 vote

Final answer:

To sterilize the glass baby bottle, a heat transfer of approximately 2.3 × 10^4 J is required.

Step-by-step explanation:

To calculate the heat transfer required to sterilize the glass baby bottle, we can use the equation:

Q = mcΔT

Where Q is the heat transfer, m is the mass of the baby bottle, c is the specific heat of the glass, and ΔT is the change in temperature.

Given that the mass of the baby bottle is 50.0 g, the specific heat of the glass is approximately 0.84 J/g°C, and the change in temperature is 95.0°C - 22.0°C = 73.0°C, we can plug these values into the equation:

Q = (50.0 g)(0.84 J/g°C)(73.0°C) = 2.3 × 10^4 J

Therefore, the required heat transfer is approximately 2.3 × 10^4 J.

answered
User Shoreki
by
8.2k points
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