asked 99.1k views
3 votes
Determine the number of atoms and the mass of zirconium, silicon, and oxygen found in 0.3384 mol of zircon, ZrSiO4, a semiprecious stone.

a) Zr: 2.04 × 10^23 atoms, Si: 1.35 × 10^24 atoms, O: 8.16 g

b) Zr: 1.35 × 10^24 atoms, Si: 2.04 × 10^23 atoms, O: 8.16 g

c) Zr: 8.16 × 10^23 atoms, Si: 1.08 × 10^24 atoms, O: 5.4 g

d) Zr: 1.08 × 10^24 atoms, Si: 8.16 × 10^23 atoms, O: 5.4 g

1 Answer

5 votes

Final answer:

In 0.3384 mol of zircon, there are 2.04 × 10^23 atoms of Zr, 1.35 × 10^24 atoms of Si, and 8.16 g of O.

Correct option is a.

Step-by-step explanation:

In 0.3384 mol of zircon, ZrSiO4, there are:

Zr: 2.04 × 1023 atoms

Si: 1.35 × 1024 atoms

O: 8.16 g

answered
User Digitaleagle
by
8.6k points
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