asked 73.0k views
23 votes
Given f(x)= 1/3(4-x)^2, what is the value of f(16)

2 Answers

5 votes

Answer:

48

Explanation:

f(x)= 1/3(4 - x)^2

f(16) = (1/3)(4 - 16)^2

f(16) = (1/3)(-12)^2

f(16) = (1/3)(144)

f(16) = 48

answered
User ToniBig
by
7.6k points
3 votes

The value of
f(16) is 48.

Solve:
f(x)=1/3(4-x)^2,

Solution:

1. Write the equation


f(x)= 1/3(4 - x)^2

2. Substitute 16 into the x


f(16) = (1/3)(4 - 16)^2

3. Simplify


f(16) = (1/3)(144)

4. Multiply


f(16) = 48

Therefore, the value of
f(16) is 48.

answered
User Engineiro
by
7.2k points

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