The minimum value of the function h(x)=2|x-1| is 0, which occurs when x equals 1.
The student asks for the minimum value of the function h(x)=2|x-1|. Since the equation involves an absolute value, the function measures the distance on the number line and will always be non-negative. At x=1, the value inside the absolute value becomes zero, making h(x) also zero.
This represents the minimum value of the function, which is 0. In terms of significance, the discussion of even and odd functions and the property of integrals over symmetric intervals does not apply directly to this question, as the function given is not within an integral, nor is it described as a probability density function.