Question

F(x)=x^2+6x+4 what is the minimum value of the function

Answer 1

-5.

Explanation:

F(x)=x^2+6x+4

We first convert to vertex form

f(x) = (x + 3)^2 - 9 + 4

--> f(x) = (x + 3)^2 - 5

The vertex of the curve is at (-3, -5).

So the minimum value of f(x) is -5.