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a security code consists of 5 digits and a digit may not be used more than once. how many possible outcomes are there

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User MChan
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Final answer:

There are 30,240 possible outcomes for a security code consisting of 5 digits, where each digit may not be used more than once.

Step-by-step explanation:

The number of possible outcomes (microstates) of a security code consisting of 5 digits, where each digit may not be used more than once, can be calculated as follows:

In the first digit, you have 10 options (0-9).

In the second digit, you have 9 options (excluding the digit you chose for the first digit).

In the third digit, you have 8 options (excluding the digits you chose for the first and second digits).

In the fourth digit, you have 7 options (excluding the digits you chose for the first, second, and third digits).

In the fifth digit, you have 6 options (excluding the digits you chose for the first, second, third, and fourth digits).

By multiplying the number of options for each digit, you get the total number of possible outcomes:

10 x 9 x 8 x 7 x 6

= 30,240.

Therefore, there are 30,240 possible outcomes for a security code consisting of 5 digits, where each digit may not be used more than once.

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User Peter Theill
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