Question

2C₂H₆ + 7O₂ = 4CO₂ + 6H₂O

what mass of 4CO₂ will be produced from the reaction of 37.5g of C₂H₆ ?

Answer 1

Starting with the balanced equation for ethane combustion, we calculated the moles of ethane and then used stoichiometry to find the mass of carbon dioxide produced, which is 109.66 grams from 37.5 grams of ethane.

Step-by-step explanation:

The chemical equation for the combustion of ethane (C2H6) is as follows:

1. Balance the equation: 2 C2H6 + 7 O2 → 4 CO2 + 6 H2O.
2. Determine the molar mass of C2H6: C (12.01 g/mol) × 2 + H (1.008 g/mol) × 6 = 30.07 g/mol.
3. Calculate the moles of C2H6: 37.5g / 30.07 g/mol = 1.246 moles of C2H6.
4. Use the stoichiometry of the reaction to find moles of CO2: 1.246 moles C2H6 × (4 moles CO2 / 2 moles C2H6) = 2.492 moles CO2.
5. Calculate the mass of CO2 produced: 2.492 moles CO2 × 44.01 g/mol = 109.66 g CO2.

Therefore, 109.66 grams of CO2 will be produced from the reaction of 37.5 g of C2H6.