Question

When conducting a restriction digest with the endonuclease Mst II, how many fragments do you expect to see from a person's PCR product who is homozygous for the normal Hb A gene?

O no fragments
O 1 fragment
O 2 fragments
O 3 fragments

Answer 1

A person who is homozygous for the normal Hb A gene would expect to see 3 fragments when conducting a restriction digest with the endonuclease Mst II.

Step-by-step explanation:

When conducting a restriction digest with the endonuclease Mst II, a person who is homozygous for the normal Hb A gene would expect to see 3 fragments in their PCR product.

Restriction digest is a process where DNA is cut into smaller fragments using restriction enzymes. Mst II is an endonuclease that recognizes a specific DNA sequence and cleaves the DNA at that site.

In the case of a homozygous individual with the normal Hb A gene, Mst II would recognize and cut the DNA in two places, resulting in three fragments.