Final answer:
The concentration of a glucose solution diluted from 24.03 mL of a 6.1 M solution to 233.49 mL is 0.630 M.
Step-by-step explanation:
The question is asking for the concentration of a glucose solution after it has been diluted. To find the molarity of the diluted solution, we can use the concept of molarity (M), defined as the number of moles of solute per liter of solution. Since the amount of solute isn't changing, only the volume, we can use the formula M1V1 = M2V2, where M1 and V1 are the molarity and volume of the initial solution, and M2 and V2 are the molarity and volume of the diluted solution.
In this problem:
- Initial molarity (M1) = 6.1 M
- Initial volume (V1) = 24.03 mL
- Final volume (V2) = 233.49 mL
- Final molarity (M2) = ? (This is what we're trying to find)
Now we plug in the known values into the equation and solve for M2:
M1V1 = M2V2
(6.1 M) × (24.03 mL) = M2 × (233.49 mL)
M2 = (6.1 M × 24.03 mL) / 233.49 mL
After performing the calculation:
M2 = 0.630 M (rounded to three significant figures)
The concentration of the diluted glucose solution is 0.630 M.