Question

Find P 20 of the following arithmetic sequence: 206, 212, 218, 224....

State:
Po =
d =
P20 =

Answer 1

`p_(20) = 1.25528`

P₀ = 206 and difference d = 6

Explanation:

Step(i):-

Given that the arithmetic sequence

206,212,218,224,.....

P₀ = 206 and difference d = 212-206 = 6

The
`n^(th)` term of the sequence

`t_(n) = ar^(n-1)`

Step(ii):-

The
`n^(th)` term of the sequence

`P_(n) = ar^(n-1)`

Put n=20

`P_(20) = 206 ( 6) ^(20-1)`

`p_(20) = 1.25528`