Final answer:
The electrical potential of a Daniel cell with unity concentrations of Zn²⁺ and Cu²⁺ can be calculated using the equation Ecell = Eᵒcell - (0.0591 V/n)log(Q), where Q is the reaction quotient. However, the specific value of Eᵒcell is not provided in the given information.
Step-by-step explanation:
The electrical potential of a Daniel cell depends on the concentrations of Zn²⁺ and Cu²⁺. When the concentrations of Zn²⁺ and Cu²⁺ are both unity, the initial voltage measured when the cell is connected can be calculated using the equation: Ecell = Eᵒcell - (0.0591 V/n)log(Q), where Q is the reaction quotient and n is the number of electrons transferred in the cell reaction.
From the given information, the reaction quotient Q = [Zn²+]/[Cu²+]. If the cell initially contains 1.0 M Cu²+ and 1.0 × 10-6 M Zn²+, then Q = (1.0 × 10-6 M)/(1.0 M) = 1.0 × 10-6. Substituting this value into the equation, we get: Ecell = Eᵒcell - (0.0591 V/n)log(1.0 × 10-6).
However, the specific value of Eᵒcell is not provided, so we cannot determine the exact electrical potential of the Daniel cell in this scenario without that information.