Question

Two airplanes bomb attack in succession. The probability of each correctly scoring a hit is 0.3 and 0.2 respectively. The second will bomb only if the first misses the target. Find the probability that the target is hit.

(a) 0.24
(b) 0.36
(c) 0.56
(d) 0.72

Answer 1

The probability that the target is hit is 0.36

Step-by-step explanation:

To find the probability that the target is hit, we need to consider the two possible scenarios: either the first airplane hits the target or it misses. If the first airplane hits the target, the probability is 0.3. If the first airplane misses, the second airplane will bomb and the probability of it hitting the target is 0.2 (since it only bombs if the first airplane misses). So, the probability of the target being hit is:

P(target hit) = P(first airplane hits) + P(first airplane misses) * P(second airplane hits) = 0.3 + 0.7 * 0.2 = 0.36