Question

Write the net ionic equation for the reaction of potassium dichromate(VI), K2Cr2O7, with sodium sulphite, Na2SO3, in an acid solution to give chromium(III) ion and the sulfate ion.

Answer 1

The net ionic equation for the reaction between potassium dichromate and sodium sulphite in an acid solution is Cr2O7^2- + 3SO3^2- + 8H+ -> 2Cr^3+ + 3SO4^2- + 4H2O.

Step-by-step explanation:

The net ionic equation for the reaction of potassium dichromate(VI), K2Cr2O7, with sodium sulphite, Na2SO3, in an acid solution to give chromium(III) ion and the sulfate ion can be written as follows:

Cr2O72- + 3 SO32- + 8 H+ → 2 Cr3+ + 3 SO42- + 4 H2O

This equation shows the reactants (dichromate and sulphite ions) on the left side, and the products (chromium(III) and sulfate ions) on the right side. The spectator ions (potassium and sodium ions) are omitted from the equation because they do not participate in the reaction.