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Calculate the work and energy change when 67.11 g Cu₂O is oxidized at a constant pressure of 1.00 bar.

a) Work and energy change are equal
b) Work is negative, energy change is positive
c) Work is positive, energy change is negative
d) Both work and energy change are zero

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User Neb
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1 Answer

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Final answer:

The work and energy change when 67.11 g of Cu₂O is oxidized at a constant pressure of 1.00 bar can be determined using the equation w = -PAV. Since the volume increases as the reaction proceeds, the work done by the system is negative, indicating that the system loses energy by performing work on its surroundings.

Step-by-step explanation:

The work and energy change when 67.11 g of Cu₂O is oxidized at a constant pressure of 1.00 bar can be determined using the equation

where w is the work done by the system, P is the external pressure, A is the change in volume, and V is the volume change.

In this case, since the volume increases as the reaction proceeds, the work done by the system is negative, indicating that the system loses energy by performing work on its surroundings. The energy change is also negative.

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User Michael Granger
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