Question

Calculate the enthalpy of reaction for the following reaction: 2Fe₂O₃(s) + 3C(s) → 4Fe(s) + 3CO₂(g)

ΔHfo(Fe₂O₃(s)) = -824.2 kJ/mol

ΔHfo(C(s)) = ?

ΔHfo(Fe(s)) = ?

ΔHfo(CO₂(g)) = -393.5 kJ/mol

Answer 1

To calculate the enthalpy of reaction for the given reaction, we can use Hess's law. By writing and adding two equations together, we can determine the enthalpy change associated with the reaction.

Step-by-step explanation:

To calculate the enthalpy of reaction for the given reaction, we need to use Hess's law. We can write two equations that can be added together to give the desired equation and for which the enthalpy changes are known.

1. Reverse Equation (1): 2 CO(g) → 2 C(s) + O₂(g) ΔH = +221.0 kJ

2. Equation (2) as given: C(s) + O₂(g) → CO₂ (s) ΔH = -393.5 kJ

Adding these two equations together, after multiplying the second equation by 2 to balance the number of C(s) on both sides, we get:

2 C(s) +2 O₂(g) → 2 CO₂ (s) ΔH = -787.0 kJ