Question

How do i write an equation that goes through the line (-10,8) with a slope of 6

Answer 1

y = 6x + 68

Explanation:

The form is y=mx+b, where m is the slope and b is the y-intercept.

We know that the slope is 6, so we substitute it for m in the equation:

y=6x+b

If we look at the graph shown below, we see that (-10, 8) has been plotted (the little dot).

Let's pretend there's an invisible 1 below 6:
`(6)/(1)` This is our slope. We can do rise over run:
`(rise)/(run)`. 6 is the rise and 1 is the run.

If we look at the second picture, we went up 6 spaces and ran 1 space. We would keep doing this until the line hits the y-axis, which is the y-intercept. The y-intercept is 68. So the equation is

y = 6x + 68

Answer 2

first plug in the slope and the given point into slope intercept form
then convert into standard form if necessary