asked 211k views
1 vote
what is the force per meter (in n/m) on a lightning bolt at the equator that carries 20,300 a perpendicular to the earth's 3.00 ✕ 10−5 t field?

1 Answer

2 votes

Final answer:

The force per meter on the lightning bolt is 0.609 N/m, and the direction of the force, determined by the right-hand rule, is due east if the lightning bolt's current is straight up and the Earth's field direction is due north.

Step-by-step explanation:

To calculate the force per meter on a lightning bolt at the equator that carries a current perpendicular to the Earth's magnetic field, we use the formula F = ILB sin(θ), where F stands for force, I is the current in amperes, L is the length in meters over which the force acts, B is the magnetic field strength in teslas, and θ is the angle between the current direction and the magnetic field.

Given that the lightning bolt carries 20,300 A and the Earth's magnetic field strength at the equator is 3.00 × 10⁻⁵ T, and the angle θ is 90 degrees since the current is perpendicular to the field:

F = (20,300 A)(1 m)(3.00 × 10⁻⁵ T) sin(90°)
F = 20,300 A × 3.00 × 10⁻⁵ T
F = 0.609 N/m

The direction of the force would be perpendicular to both the current flow and the magnetic field direction, which is determined by the right-hand rule. Here, if the lightning bolt's current is straight up and the magnetic field direction is due north, the force acts due east.

answered
User James Schek
by
9.0k points