Final answer:
The VSEPR shape of BH3 is trigonal planar, with the three hydrogen atoms and the boron atom lying in the same plane and bond angles of 120 degrees.
Step-by-step explanation:
The VSEPR shape of BH₃ is trigonal planar. Boron in BH₃ has three valence electrons and forms three bonds with hydrogen atoms, with no lone pairs on the boron atom. This setup leads to three regions of electron density that try to get as far apart from each other as possible. According to the VSEPR model, this arrangement of electron domains corresponds to a trigonal planar geometry, where the atoms lie in the same plane and the H-B-H bond angles are 120°.