Question

How many grams of glucose are required to prepare 500 mL of a 0.5 M solution?

A. 18 g

B. 27 g

C. 45 g

D. 90 g

Answer 1

To prepare 500 mL of a 0.5 M glucose solution, one would need 45.04 g of glucose, which rounds to the closest answer choice, C. 45 g.

Step-by-step explanation:

To calculate the amount of glucose needed to prepare 500 mL of a 0.5 M solution, you can follow these steps:

1. Calculate the number of moles of glucose required using the formula: Molarity (M) = Moles of solute (mol) / Volume of solution (L).
   In this case, to find the moles needed: 0.5 mol/L x 0.500 L = 0.250 mol.
2. Multiply the number of moles by the molar mass of glucose to find the mass in grams.
   The molar mass of glucose (C6H12O6) is 180.16 g/mol.
   Therefore, mass = 0.250 mol x 180.16 g/mol = 45.04 g.

Since the mass of glucose needed is 45.04 g and the options are rounded to the nearest whole number, the closest option is C. 45 g.