asked 91.3k views
1 vote
Which species acts as the limiting reactant if 289g of copper(ii) sulfate is allowed to react with 189g of zinc. A) Copper(II) sulfate

B) Zinc
C) Both are in excess
D) Cannot be determined without the balanced equation

2 Answers

7 votes

Answer:

d cuso4

Step-by-step explanation:

answered
User Mrcoulson
by
8.4k points
3 votes

Final answer:

Copper(ii) sulfate is the limiting reactant when 289g of copper(ii) sulfate reacts with 189g of zinc.

Step-by-step explanation:

In order to determine the limiting reactant, we need to compare the number of moles of each reactant. To find the moles, we divide the given mass by the molar mass of each compound.

For copper(ii) sulfate (CuSO4):

Mass = 289g, Molar mass = 63.55g/mol (copper) + 32.07g/mol (sulfur) + 4(16.00g/mol) (oxygen) = 159.62g/mol

Moles = 289g / 159.62g/mol = 1.8104 mol

For zinc (Zn):

Mass = 189g, Molar mass = 65.38g/mol

Moles = 189g / 65.38g/mol = 2.8906 mol

From the given masses, we can see that there are fewer moles of copper(ii) sulfate compared to zinc. Therefore, copper(ii) sulfate is the limiting reactant.

answered
User Lockstock
by
8.2k points
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