Question

Arrange these elements in order of decreasing first ionization energy: cl, s, sn, pb?

Option 1: Pb, Sn, Cl, S
Option 2: Sn, Pb, Cl, S
Option 3: Pb, Sn, S, Cl
Option 4: Sn, Pb, S, Cl

Answer 1

The correct arrangement of these elements in order of decreasing first ionization energy is Option 1: Pb, Sn, Cl, S. Lead (Pb) has the highest first ionization energy among the given elements, followed by Tin (Sn), Chlorine (Cl), and Sulfur (S).

Step-by-step explanation:

The correct arrangement of these elements in order of decreasing first ionization energy is Option 1: Pb, Sn, Cl, S.

Ionization energy refers to the amount of energy required to remove an electron from an atom or ion. Generally, ionization energy increases from left to right across a period and decreases from top to bottom within a group in the periodic table.

Lead (Pb) has the highest first ionization energy among the given elements, followed by Tin (Sn), Chlorine (Cl), and Sulfur (S).