asked 111k views
3 votes
F(x,y)=3x−6y over the triangle with vertices (0, 0), (6, 0), and (0, 7).

Options:
a) Maximum: 18, Minimum: -42
b) Maximum: 12, Minimum: -36
c) Maximum: 24, Minimum: -30
d) Maximum: 15, Minimum: -48

asked
User Luke Liu
by
7.5k points

1 Answer

0 votes

Final answer:

The maximum and minimum values of the function f(x, y) = 3x - 6y over a given triangle with vertices (0, 0), (6, 0), and (0, 7) are 18 and -42 respectively.

Step-by-step explanation:

The question is asking us to find the maximum and minimum values of the function f(x, y) = 3x - 6y over a given triangle with vertices (0, 0), (6, 0), and (0, 7).

To find the maximum and minimum values, we need to evaluate the function at the vertices of the triangle.

Plugging in the coordinates of the vertices into the function, we get f(0, 0) = 0, f(6, 0) = 18, and f(0, 7) = -42. Therefore, the answer is Option a) Maximum: 18, Minimum: -42.

answered
User Jagadesh Seeram
by
8.0k points
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.