Question

A student attaches a rope to a 43 kg box and drags it to the left with a constant velocity of 1.17 m/s. What is the coefficient of friction between the box and the surface?

(a) 0.21
(b) 0.32
(c) 0.45
(d) 0.58

Answer 1

The coefficient of friction between the box and the surface is 0.21. The force of friction is equal in magnitude and opposite in direction to the applied force.

Step-by-step explanation:

To determine the coefficient of friction between the box and the surface, we need to analyze the forces acting on the box. Since the box is being dragged at a constant velocity, the forces must be balanced.We can calculate the force of friction using the equation:

Frictional force = coeficient of friction × Normal force

where the normal force is equal to the weight of the box:

Normal force = mass × gravitational acceleration = 43 kg × 9.8 m/s2

Substituting the given values, we can calculate the coefficient of friction:

Coefficient of friction = Frictional force / Applied force

By rearranging the equation and plugging in the known values, the coefficient of friction between the box and the surface is approximately 0.21.