Question

A basketball player makes 60% of his free throws.

A) 50%
B) 40%
C) 30%
D) 60%

Answer 1

The probability that Helen makes both free throws is 63.75%.

Step-by-step explanation:

The probability that Helen makes both free throws can be determined by multiplying the probability that she makes the first free throw (P(C)) by the probability that she makes the second free throw given that she made the first (P(D|C)).

So, P(Helen makes both free throws) = P(C) * P(D|C) = 0.75 * 0.85 = 0.6375.

Therefore, the probability that Helen makes both free throws is 0.6375 or 63.75%.